5[2(x+4)-x]=2(3x+19)

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Solution for 5[2(x+4)-x]=2(3x+19) equation:


Simplifying
5[2(x + 4) + -1x] = 2(3x + 19)

Reorder the terms:
5[2(4 + x) + -1x] = 2(3x + 19)
5[(4 * 2 + x * 2) + -1x] = 2(3x + 19)
5[(8 + 2x) + -1x] = 2(3x + 19)

Combine like terms: 2x + -1x = 1x
5[8 + 1x] = 2(3x + 19)
[8 * 5 + 1x * 5] = 2(3x + 19)
[40 + 5x] = 2(3x + 19)

Reorder the terms:
40 + 5x = 2(19 + 3x)
40 + 5x = (19 * 2 + 3x * 2)
40 + 5x = (38 + 6x)

Solving
40 + 5x = 38 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
40 + 5x + -6x = 38 + 6x + -6x

Combine like terms: 5x + -6x = -1x
40 + -1x = 38 + 6x + -6x

Combine like terms: 6x + -6x = 0
40 + -1x = 38 + 0
40 + -1x = 38

Add '-40' to each side of the equation.
40 + -40 + -1x = 38 + -40

Combine like terms: 40 + -40 = 0
0 + -1x = 38 + -40
-1x = 38 + -40

Combine like terms: 38 + -40 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2

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